>>> re.findall(r"a(\d+?)","a23b") # 非贪婪模式 ['2'] >>> re.findall(r"a(\d+)","a23b") ['23']
>>> re.findall(r"a(\d+)b","a23b") ['23'] >>> re.findall(r"a(\d+?)b","a23b") #如果前后均有限定条件,则非匹配模式失效 ['23']
>>> re.findall(r"a(\d+)b.+a(\d+)b","a23b\na34b") [] >>> re.findall(r"a(\d+)b.+a(\d+)b","a23b\na34b",re.S) [('23','34')] >>>
>>> re.findall(r"^a(\d+)b","a23b\na34b") ['23'] >>> re.findall(r"^a(\d+)b","a23b\na34b",re.M) ['23','34']
>>> re.findall(r"a(\d+)b","a23b\na34b") ['23','43']
import re n='''12 drummers drumming, 11 pipers piping, 10 lords a-leaping''' p=re测试数据pile('^\d+') p_multi=re测试数据pile('^\d+',re.MULTILINE) #设置 MULTILINE 标志 print re.findall(p,n) #['12'] print re.findall(p_multi,n) # ['12', '11']
import re a = 'a23b' print re.findall('a(\d+?)',a) #['2'] print re.findall('a(\d+)',a) #['23'] print re.findall(r'a(\d+)b',a) #['23'] print re.findall(r'a(\d+?)b',a) # ['23']
b='a23b\na34b' ''' . 匹配非换行符的任意一个字符''' print re.findall(r'a(\d+)b.+a(\d+)b',b) #[] print re.findall(r'a(\d+)b',b,re.M) # ['23', '34'] print re.findall(r'^a(\d+)b',b,re.M) # ['23', '34'] print re.findall(r'a(\d+)b',b) #['23','34'] 可以匹配多行 print re.findall(r'^a(\d+)b',b) # ['23'] 默认^只会匹配符合正则的第一行 print re.findall(r'a(\d+)b$',b) # ['34'] 默认$只会匹配符合正则的末行 print re.findall(r'a(\d+)b',b,re.M) #['23', '34'] print re.findall(r'a(\d+)b.?',b,re.M) # ['23', '34'] 表达式中的'.'匹配除换行符以外的字符,'?'匹配前一个字符0次或1次 print re.findall(r"a(\d+)b", "a23b\na34b") # ['23', '34']
注: Python3.4中,print为函数,需要加括号
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