今天带来python/golang 删除链表中的元素教程详解
先用使用常规方法，两个指针:
golang实现：
type Node struct { value int next *Node } type Link struct { head *Node tail *Node lenth int } // 向链表中添加元素 func (link *Link) add(v int) { if link.lenth == 0 { // 当前链表是空链表 link.head = &Node{v, nil} link.tail = link.head link.lenth = 1 } else { newNond := &Node{v, nil} link.tail.next = newNond link.tail = newNond link.lenth += 1 } } // 删除链表中的元素(双指针) func (link *Link) remove(v int) { if link.lenth == 0 { fmt.Println("空链表，不支持该操作") return } var previous *Node = nil for current := link.head; current != nil; current = current.next { if current.value == v { if current == link.head { // 要删除的是头节点 link.head = current.next } else if current == link.tail { // 要删除的是尾节点 previous.next = nil link.tail = previous } else { // 要删除的是中间的节点 previous.next = current.next } link.lenth -= 1 break } previous = current } } // 打印链表 func (link *Link) printList() { if link.lenth == 0 { fmt.Println("空链表") return } for cur := link.head; cur != nil; cur = cur.next { fmt.Printf("%d ", cur.value) } fmt.Println() }
python实现:
class Node: def __init__(self, value, next): self.value = value self.next = next def __str__(self): return str(self.value) class Link: def __init__(self): self.head = None self.tail = None self.lenth = 0 # 向链表中添加元素 def add(self, v): if self.lenth == 0: # 当前链表是空链表 self.head = Node(v, None) self.tail = self.head self.lenth = 1 else: new_node = Node(v, None) self.tail.next = new_node self.tail = new_node self.lenth += 1 # 打印链表 def print(self): if self.lenth == 0: print('空链表') return cur = self.head while True: if cur == None: print() break print(cur, end=' ') cur = cur.next # 删除链表中的元素 def remove(self, v): if self.lenth == 0: return cur = self.head pre = None while True: if cur.value == v: if cur == self.head: # 要删除的是头节点 self.head = cur.next elif cur == self.tail: # 要删除的是尾节点 pre.next = None self.tail = pre else: # 要删除的是中间的节点 pre.next = cur.next self.lenth -= 1 break pre = cur cur = cur.next if cur == None: print("未找到", v) break
只使用使用一个指针实现链表的删除：
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