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代码分析Java中线程的等待与唤醒

我们先来看一下实例代码:

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class threada extends thread{

 

   public threada(string name) {

     super (name);

   }

 

   public void run() {

     synchronized ( this ) {

       system.out.println(thread.currentthread().getname()+ " call notify()" );

       notify();

     }

   }

}

public class waittest {

   public static void main(string[] args) {

     threada t1 = new threada( "t1" );

     synchronized (t1) {

       try {

         // 启动[线程t1]

         system.out.println(thread.currentthread().getname()+ " start t1" );

         t1.start();

 

         // 主线程等待t1通过notify()唤醒。

         system.out.println(thread.currentthread().getname()+ " wait()" );

         t1.wait();

 

         system.out.println(thread.currentthread().getname()+ " continue" );

       } catch (interruptedexception e) {

         e.printstacktrace();

       }

     }

   }

}

输出结果:main start t1 -> main wait() -> t1 call notify() -> main continue

其实调用t1.start(),t1为就绪状态,只是main方法中,t1被main线程锁住了,t1.wait()的时候,让当前线程等待,其实是让main线程等待了,然后释放了t1锁,t1线程执行,打印t1 call notify(),然后唤醒main线程,最后结束;

这里说一下wait()与sleep()的区别,他们的共同点都是让线程休眠,但是wait()会释放对象同步锁,而sleep()不会;下面的代码t1结束之后才会运行t2;能够证实这一点;

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public class sleeplocktest{

   private static object obj = new object();

   public static void main(string[] args){

     threada t1 = new threada( "t1" );

     threada t2 = new threada( "t2" );

     t1.start();

     t2.start();

   }

   static class threada extends thread{

     public threada(string name){

       super (name);

     }

     public void run(){

       synchronized (obj) {

         try {

           for ( int i= 0 ; i < 10 ; i++){

             system.out.printf( "%s: %d\n" , this .getname(), i);

             // i能被4整除时,休眠100毫秒

             if (i% 4 == 0 )

               thread.sleep( 100 );

           }

         } catch (interruptedexception e) {

           e.printstacktrace();

         }

       }

     }

   }

}

 

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