1. 概念
<< 左移运算符，左移是在后面补0， num << 1,相当于num乘以2
>> 右移运算符, 右移是在前面补1或0，num >> 1, 相当于num除以2
>>> 无符号右移，是在前面补0， 忽略符号位，空位都以0补齐
另外， 不论是左右还是右移32位，相当于不移动，还是原值。
实际上 在java虚拟机执行这句代码的时候如下这样执行的：
5>>(n%32)--->结果
你这里n=32 ；所以5>>32即是 5>>(32%32)-->5>>0 的结果；
2. 测试代码
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public class test{ public test(){ system.out.println( "=============算术右移 >> ===========" ); int i= 0xc0000000 ; system.out.println( "移位前：i= " +i+ " = " +integer.tobinarystring(i)+ "(b)" ); i=i>> 28 ; system.out.println( "移位后：i= " +i+ " = " +integer.tobinarystring(i)+ "(b)" );
system.out.println( "---------------------------------" );
int j= 0x0c000000 ; system.out.println( "移位前：j= " +j+ " = " +integer.tobinarystring(j)+ "(b)" ); j=j>> 24 ; system.out.println( "移位后：j= " +j+ " = " +integer.tobinarystring(j)+ "(b)" );
system.out.println( "\n" ); system.out.println( "==============逻辑右移 >>> =============" ); int m= 0xc0000000 ; system.out.println( "移位前：m= " +m+ " = " +integer.tobinarystring(m)+ "(b)" ); m=m >>> 28 ; system.out.println( "移位后：m= " +m+ " = " +integer.tobinarystring(m)+ "(b)" );
system.out.println( "---------------------------------" );
int n= 0x0c000000 ; system.out.println( "移位前：n= " +n+ " = " +integer.tobinarystring(n)+ "(b)" ); n=n>> 24 ; system.out.println( "移位后：n= " +n+ " = " +integer.tobinarystring(n)+ "(b)" );
system.out.println( "\n" ); system.out.println( "==============移位符号的取模===============" ); int a= 0xcc000000 ; system.out.println( "移位前：a= " +a+ " = " +integer.tobinarystring(a)+ "(b)" ); system.out.println( "算术右移32：a=" +(a>> 32 )+ " = " +integer.tobinarystring(a>> 32 )+ "(b)" ); system.out.println( "逻辑右移32：a=" +(a>>> 32 )+ " = " +integer.tobinarystring(a>>> 32 )+ "(b)" );
system.out.println( "算术右移64：a=" +(a>> 64 )+ " = " +integer.tobinarystring(a>> 64 )+ "(b)" ); system.out.println( "逻辑右移64：a=" +(a>>> 64 )+ " = " +integer.tobinarystring(a>>> 64 )+ "(b)" );
}
public static void main(string[] args){ new test(); }
} |
运行结果：
=============算术右移 >> ===========
移位前：i= -1073741824 = 11000000000000000000000000000000(b)
移位后：i= -4 = 11111111111111111111111111111100(b)
移位前：j= 201326592 = 1100000000000000000000000000(b)
移位后：j= 12 = 1100(b)
==============逻辑右移 >>> =============
移位前：m= -1073741824 = 11000000000000000000000000000000(b)
移位后：m= 12 = 1100(b)
移位前：n= 201326592 = 1100000000000000000000000000(b)
移位后：n= 12 = 1100(b)
==============移位符号的取模===============
移位前：a= -872415232 = 11001100000000000000000000000000(b)
算术右移32：a=-872415232 = 11001100000000000000000000000000(b)
逻辑右移32：a=-872415232 = 11001100000000000000000000000000(b)
算术右移64：a=-872415232 = 11001100000000000000000000000000(b)
逻辑右移64：a=-872415232 = 11001100000000000000000000000000(b)
3. 为什么没有无符号左移
这个问题大家可以思考一下，应该能想出来。（提示：没有就是没有存在的意思）
以上所述是小编给大家介绍的java中的移动位运算：,>>>详解整合，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对网站的支持！
原文链接：https://blog.csdn.net/weixin_34414196/article/details/87551511
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