Java模拟ATM机，供大家参考，具体内容如下
实现登录，查询，转账，取款，修改密码，退出功能。
源码
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package bank;
import java.io.*; import java.util.Scanner;
//ATM类 public class Atm { private String[] user; //用户全部信息 private double money; //修改钱数 private double userMoney; //用户的钱 private String newPassword; private String userInFo; private int index; private int a = 0 ; private int count = 10 ;
public void show(){ //显示界面 index = logIn(); if (index != - 1 ){ working(); } }
private String[] newStringUser(String[] str){ count=count+ 10 ; String[] newUser = new String[count]; for ( int i= 0 ;i<a;i++) newUser[i] = str[i]; return newUser; }
private void getUser(){ //从文件获取全部用户 String str; String[] strings = new String[count]; File file = new File( "src\\bank\\user" ); FileReader fileReader = null ; BufferedReader bufferedReader = null ; try { fileReader = new FileReader(file); bufferedReader = new BufferedReader(fileReader); while ((str = bufferedReader.readLine())!= null ){ if (a<=count) strings[a++] = str; else strings = newStringUser(strings); } user = new String[a]; for ( int i= 0 ;i<a;i++) user[i] = strings[i]; strings = null ; } catch (Exception e){ e.printStackTrace(); if ((fileReader!= null )&&(bufferedReader!= null )){ try { bufferedReader.close(); fileReader.close(); } catch (IOException e1) { e1.printStackTrace(); } } } }
private int logIn(){ //用户登录 getUser(); String name,password,user; String[] a; int i = 0 ; int number = - 1 ; Scanner input = new Scanner(System.in); a: while (i< 3 ){ System.out.println( "请输入用户名：" ); name = input.nextLine(); System.out.println( "请输入用户密码：" ); password = input.nextLine(); user = name + "*" + password; for ( int j= 0 ;j< this .user.length;j++){ a = this .user[j].split( "\\*" ); userInFo = a[ 0 ]+ "*" +a[ 1 ]; if (userInFo.equals(user)){ number = j; break a; } } i++; System.out.println( "账户或密码错误请重新输入。。。" ); } if (number!=- 1 ){ System.out.println( "登录成功" ); try { Thread.sleep( 1000 ); } catch (Exception e){ e.printStackTrace(); } } else System.out.println( "您已输入错误三次，卡已被吞！请到银行柜台询问！" ); return number; }
private int anthorLogin(){ //查询转账用户是否存在 Scanner input = new Scanner(System.in); String antherUserName; String[] a; int x=- 1 ; System.out.println( "请输入要转账的用户名：" ); antherUserName = input.nextLine(); for ( int i= 0 ;i<user.length;i++){ a = this .user[i].split( "\\*" ); if (a[ 0 ].equals(antherUserName)){ x=i; break ; } } return x; }
private void show1(){ System.out.println( "**********************" ); System.out.println( "\t欢迎使用ATM" ); System.out.println( "1，账户余额查询\n2，存钱\n3，取钱\n4，转账\n5，修改用户密码\n6，退出系统\n" ); System.out.println( "**********************" ); }
private void changeUser( int x){ //改变用户数组里的数据 String[] str = user[index].split( "\\*" ); if (x== 1 ) user[index] = str[ 0 ]+ "*" +newPassword+ "*" +str[ 2 ]; else user[index] = str[ 0 ]+ "*" +str[ 1 ]+ "*" +userMoney; }
private void working(){ //atm办理的业务 String number; setMoney(); do { show1(); System.out.println( "请输入要办理的业务序号：" ); Scanner input = new Scanner(System.in); number = input.nextLine(); switch (number){ case "1" : look(); break ; case "2" : saveMoney(); break ; case "3" : getMoney(); break ; case "4" : giveMoney(); break ; case "5" : changePassword(); break ; case "6" : System.out.println( "欢迎下次光临！" ); write(); break ; default : System.out.println( "您输入有误，请重新输入。。。。" ); } } while (!number.equals( "6" )); }
private void setMoney(){ String u = user[index]; userMoney = Double.parseDouble(u.split( "\\*" )[ 2 ]); }
private void look(){ //办理查看余额业务 System.out.println( "用户余额为：" +userMoney); try { Thread.sleep( 2000 ); } catch (Exception e){ e.printStackTrace(); } }
private void saveMoney(){ //办理存钱业务 money = howMuch( "存钱" ); userMoney = userMoney+money; changeUser( 2 ); look(); if (isContinue()) saveMoney(); }
private void getMoney(){ //办理取钱业务 money = howMuch( "取钱" ); if (money <= userMoney){ userMoney = userMoney-money; changeUser( 2 ); look(); if (isContinue()) getMoney(); } else System.out.println( "您的余额不足！" ); }
private void giveMoney(){ //办理转账业务 int anthorIndex = anthorLogin(); if (anthorIndex!=- 1 ){ money = howMuch( "转账" ); if (money <= userMoney){ userMoney = userMoney - money; changeUser( 2 ); String anthorUser = user[anthorIndex]; String[] str =anthorUser.split( "\\*" ); double money1 = Double.parseDouble(str[ 2 ]); money = money + money1; user[anthorIndex] = str[ 0 ]+ "*" +str[ 1 ]+ "*" +money; System.out.println( "转账成功！" ); look(); } else System.out.println( "您的余额不足！" ); } else System.out.println( "该用户不存在。。。。" ); }
private double howMuch(String str){ System.out.println( "欢迎办理" +str+ "业务。。。。。。" ); System.out.println( "请输入金额(只能是整数且是100的倍数，最多为10000)：" ); Scanner input = new Scanner(System.in); double money = input.nextDouble(); if (money% 10 == 0 ) return money; else { System.out.println( "您输入有误！" ); return 0.0 ; } }
private void changePassword(){ //办理修改密码业务 System.out.println( "请输入新密码：" ); Scanner input = new Scanner(System.in); newPassword = input.nextLine(); changeUser( 1 ); System.out.println( "密码修改成功！" ); }
private boolean isContinue(){ System.out.println( "是否继续办理该项业务？(请输入Y(y)/N(n))" ); Scanner input = new Scanner(System.in); String str = input.nextLine(); if (str.equalsIgnoreCase( "y" )) return true ; else return false ; }
private void write(){ String str = "" ; String s; for ( int i= 0 ;i<user.length;i++){ s = user[i]; if (i!=user.length- 1 ) str = str + s + "\n" ; else str = str + s; } File file = new File( "src\\bank\\user" ); FileWriter out = null ; try { out = new FileWriter(file); out.write(str); out.flush(); } catch (IOException e) { e.printStackTrace(); } finally { if (out != null ){ try { out.close(); } catch (IOException e) { e.printStackTrace(); } } } } } |
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package bank;
//银行类 public class Bank {
private Atm atm = new Atm();
public void welcome(User user){ System.out.println( "欢迎使用atm" ); user.useAtm(atm); }
} |
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package bank;
//用户类 public class User {
public void useAtm(Atm atm){ atm.show(); } } |
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//创建user文件当数据库 张三*456*100.0 李四*123*300.0 王五*789*200.0 |
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package bank;
//测试类 public class Text { public static void main(String[] args){ Bank bank = new Bank(); User user = new User(); bank.welcome(user); } } |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。
原文链接：https://blog.csdn.net/weixin_46085748/article/details/112017717