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java实战之猜字小游戏

一、题目描述

二、思路

语法基础:StringBuilder 类似列表,可以更改元素。

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package Practice;

 

public class tt {

     public static void main(String[] args) {

         String str = "banana" ;

         System.out.println(str.indexOf( 'z' )); // -1

         System.out.println(str.indexOf( 'a' , 2 )); // 3

 

         StringBuilder words = new StringBuilder();

         for ( int i = 0 ; i < 5 ; i++)

             words.append( '*' ); // "*****"

         System.out.println(words.length()); // 5

         System.out.println(words.indexOf( "a" )); // -1

         System.out.println(words.indexOf( "*" , 1 )); // 1

         words.setCharAt( 3 , 'a' ); // "***a*"

         System.out.println(words);

     }

}

三、代码

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package Practice;

 

import java.util.Scanner;

 

public class Guess {

     public static String words[] = { "banana" , "telecommunication" , "programming" , "bupt" };

     public static boolean [] guessed = new boolean [words.length]; // 判断猜过

     public static int num_guessed = 0 ; // 猜过的单词数量

     public static char keep; // 是否继续y or n

 

     public static void main(String[] args) {

//        for(int i = 0; i < guessed.length; i ++ ) System.out.println(guessed[i]);

         Scanner scanner = new Scanner(System.in);

 

         do {

             // 随机产生要猜测的单词  ans

             int index = ( int ) (Math.random() * words.length);

             String ans = words[index];

             // 再来一次时的重复检测

             while (guessed[index] == true )

             {

                 index = ( int ) (Math.random() * words.length);

                 ans = words[index];

             }

 

             // 初始化,StringBuilder类似list

             StringBuilder guessedWord = new StringBuilder();

             for ( int i = 0 ; i < ans.length(); i++)

                 guessedWord.append( '*' );

 

             int numberOfCorrectLettersGuessed = 0 , numberOfMisses = 0 ;

 

             // 模拟过程

             while (numberOfCorrectLettersGuessed < ans.length()) {

                 System.out.print( "(Guess) Enter a letter in word " + guessedWord

                         + " > " );

                 String s = scanner.nextLine();

                 char letter = s.charAt( 0 );

 

                 if (guessedWord.indexOf(letter + "" ) >= 0 ) { // 猜中,但重复,不算错误次数

                     System.out.println( "\t" + letter + " is already in the word" );

                 } else if (ans.indexOf(letter) < 0 ) { // 猜错

                     System.out.println( "\t" + letter + " is not in the word" );

                     numberOfMisses++;

                 } else { // 猜中,进行标记与赋值

                     int k = ans.indexOf(letter);

                     while (k >= 0 ) {

                         guessedWord.setCharAt(k, letter);

                         numberOfCorrectLettersGuessed++;

                         k = ans.indexOf(letter, k + 1 );

                     }

                 }

             }

 

             System.out.println( "The word is " + ans + ". You missed "

                     + numberOfMisses + ((numberOfMisses <= 1 ) ? " time" : " times" ));

 

             guessed[index] = true ;

             num_guessed += 1 ;

 

             if (num_guessed < words.length)

             {

                 System.out.print( "Do you want to guess for another word? Enter y or n> " );

                 keep = scanner.nextLine().charAt( 0 );

             }

 

         } while (keep == 'y' && num_guessed < words.length);

 

         if (keep == 'y' )

             System.out.println( "Perfect!!!" );

         else

             System.out.println( "You have guessed " + num_guessed + ((num_guessed <= 1 ) ? " word~" : " words~" ));

 

 

     }

}

四、效果图

全部猜完


中途退出

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原文链接:https://blog.csdn.net/whq___/article/details/115861711

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