解析string类型的xml字符串
我先拼接一个xml格式的字符串，模拟获取了这样的数据，然后再解析
所需要的包自行导入
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StringBuilder sb = new StringBuilder(); sb.append( "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" ); sb.append( "<root>" ); sb.append( " <header>" ); sb.append( " <mark>" + "this is a mark！" + "</mark>" ); sb.append( " </header>" ); sb.append( " <body>" ); sb.append( " <data>" ); sb.append( " <first>" ); sb.append( " <second>" + "来解析我啊！" + "</second>" ); sb.append( " </first>" ); sb.append( " </data>" ); sb.append( " </body>" ); sb.append( "</root>" ); //开始解析 String str= sb.toString(); Document doc = null ; try { doc = DocumentHelper.parseText(str); } catch (DocumentException e) { e.printStackTrace(); } Element root = doc.getRootElement(); // 指向根节点 <root> try { Element mark=root.element( "header" ).element( "mark" ); Element second=root.element( "body" ).element( "data" ).element( "first" ).element( "second" ); //获取xml的节点内容 System.out.println(mark.getTextTrim()); System.out.println(second.getTextTrim()); } catch (Exception e){ e.printStackTrace(); } |
运行结果：
解析String类型t复杂xml,多级节点,最好的例子
需要用jar包 dom4j-1.6.1.jar
字符串xml如下
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< root > < flw > < name >aa</ name > < age >22</ age > < instance_info > < num >1</ num > < code >0</ code > < instance > < ip >10.1.1.2</ ip > < mask >9999</ mask > </ instance > < instance > < ip >10.1.1.5</ ip > < mask >717</ mask > </ instance > </ instance_info >
< instance_info > < num >2</ num > < code >33</ code > < instance > < ip >10.1.1.2</ ip > < mask >9999</ mask > </ instance > < instance > < ip >10.1.1.9</ ip > < mask >878</ mask > </ instance > </ instance_info > </ flw > </ root > |
解析代码
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import java.io.ByteArrayInputStream; import java.io.UnsupportedEncodingException; import java.util.Iterator; import org.dom4j.DocumentException; import org.dom4j.io.SAXReader; public class XMLParser { public static void main(String[] args) { String xml = "<root><flw><name>aa</name><age>22</age><instance_info><num>1</num><code>0</code><instance><ip>10.1.1.2</ip><mask>9999</mask></instance><instance><ip>10.1.1.5</ip><mask>717</mask></instance></instance_info><instance_info><num>2</num><code>33</code><instance><ip>10.1.1.2</ip><mask>9999</mask></instance><instance><ip>10.1.1.9</ip><mask>878</mask></instance></instance_info></flw></root>" ;
long start = System.currentTimeMillis();
SAXReader reader = new SAXReader(); try { org.dom4j.Document doc = reader.read( new ByteArrayInputStream(xml .getBytes( "UTF-8" ))); org.dom4j.Element root = doc.getRootElement(); org.dom4j.Element element; org.dom4j.Element element2; org.dom4j.Element element3; for (Iterator i = root.elementIterator( "flw" ); i.hasNext();) { element = (org.dom4j.Element) i.next(); System.out .println( "name:[" + element.elementText( "name" ) + "]" ); System.out.println( "age:[" + element.elementText( "age" ) + "]" ); for (Iterator j = element.elementIterator( "instance_info" ); j .hasNext();) { element2 = (org.dom4j.Element) j.next(); System.out.println( "\tnum:[" + element2.elementText( "num" ) + "]" ); System.out.println( "\tcode:[" + element2.elementText( "code" ) + "]" ); for (Iterator k = element2.elementIterator( "instance" ); k .hasNext();) { element3 = (org.dom4j.Element) k.next(); System.out.println( "\t\tip:[" + element3.elementText( "ip" ) + "]" ); System.out.println( "\t\tmask:[" + element3.elementText( "mask" ) + "]" ); } } } } catch (DocumentException e) { e.printStackTrace(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } long end = System.currentTimeMillis(); System.out.println( "耗时：" + (end - start) + "ms" ); } } |
以上为个人经验，希望能给大家一个参考，也希望大家多多支持。
原文链接：https://blog.csdn.net/qq_33532644/article/details/84959272
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