操作的List<T>声明
oldList
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List<String> oldList = new ArrayList<>(); oldList.add( "a" ); oldList.add( "b" ); oldList.add( "c" ); System.out.println( "oldList ## " + oldList); |
newList
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List<String> newList = new ArrayList<>(); newList.add( "a" ); newList.add( "1" ); newList.add( "2" ); System.out.println( "newList ## " + newList); |
求交集 retainAll()
1. oldList 与 newList 的交集
1 2 |
oldList.retainAll(newList); System.out.println( "求交集 ## " + oldList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求交集 ## [a]
2. newList 与 oldList 的交集
1 2 |
newList.retainAll(oldList); System.out.println( "求交集 ## " + newList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求交集 ## [a]
求差集 removeAll()
1. oldList 与 newList 的差集
1 2 |
oldList.removeAll(newList); System.out.println( "oldList.removeAll(newList); --> 求差集( 在 oldList 集合中,删掉 oldList 与 newList 中都有的元素): ## " + oldList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
oldList.removeAll(newList); --> 求差集( 在 oldList 集合中,删掉 oldList 与 newList 中都有的元素): ## [b, c]
2. newList与 oldList 的差集
1 2 |
newList.removeAll(oldList); System.out.println( "newList.removeAll(oldList); --> 求差集( 在 newList 集合中,删掉 oldList 与 newList 中都有的元素): ## " + newList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
newList.removeAll(oldList); --> 求差集( 在 newList 集合中,删掉 oldList 与 newList 中都有的元素): ## [1, 2]
3. 源码解析
removeAll() 的源码
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public boolean removeAll(Collection<?> c) { Objects.requireNonNull(c); return batchRemove(c, false ); } |
batchRemove的源码
(如果传的第二个参数是false,保留差集;如果传的是true,保留的是交集)
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private boolean batchRemove(Collection<?> c, boolean complement) { final Object[] elementData = this .elementData; int r = 0 , w = 0 ; boolean modified = false ; try { for (; r < size; r++) if (c.contains(elementData[r]) == complement) elementData[w++] = elementData[r]; } finally { // Preserve behavioral compatibility with AbstractCollection, // even if c.contains() throws. if (r != size) { System.arraycopy(elementData, r, elementData, w, size - r); w += size - r; } if (w != size) { // clear to let GC do its work for ( int i = w; i < size; i++) elementData[i] = null ; modCount += size - w; size = w; modified = true ; } } return modified; } |
求并集 addAll()
1. oldList 与 newList 的并集
1 2 |
oldList.addAll(newList); System.out.println( "求并集 ##" + oldList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求并集 ##[a, b, c, a, 1, 2]
2. newList 与 oldList 的并集
1 2 |
newList.addAll(oldList); System.out.println( "求并集 ##" + newList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求并集 ##[a, 1, 2, a, b, c]
求去重后的并集
1. oldList 与 newList 去重后的并集
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oldList.removeAll(newList); // 先求差集得到去除相同项后的 oldList oldList.addAll(newList); // 再求并集 System.out.println( "求并集 ## " + oldList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求并集 ## [b, c, a, 1, 2]
2. newList与 oldList 去重后的并集
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newList.removeAll(oldList); newList.addAll(oldList); System.out.println( "求并集 ## " + newList); |
响应
oldList ## [a, b, c]
newList ## [a, 1, 2]
求并集 ## [1, 2, a, b, c]
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原文链接:https://blog.csdn.net/weixin_42166505/article/details/122627025
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