CodeforcesRound#277(Div.2)-A.CalculatingFunction（规

Calculating Function

解题思路：大水题一枚，直接找规律。n%2==0时，f = n/2; 否则，f = -(n+1)/2.

AC代码：

#include  #include  #include  #include #include  #include  #include  #include  #include  #include  #include  #include  using namespace std;#define INF 0x7fffffffint main(){//    #ifdef sxk//        freopen("in.txt","r",stdin);//    #endif    long long n;    while(scanf("%lld",&n)!=EOF)    {        if(n & 1) printf("%lld\n", -(n+1)/2);        else printf("%lld\n", n/2);    }    return 0;} 

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